Serbian tennis player, Laslo Dere has made it into the quarterfinals of the 2019 ATP Brasil Open where he will play against Felix Auger Aliassime from Canada.
Laslo Dere won his previous match in 3 sets as he beat the number 2 seed. It was a closely contested match which was eventually decided by a final set tiebreaker which Dere won. During the win, Dere impressed with his serving as he won 66% of his service points which resulted in him winning 87% of his service games. Dere held his composure well during the match as he was much more clinical during the tiebreaker which decided the contest. Dere has been in very good form over the past few weeks as he won the Rio Open prior to this tournament.
On the other side of the court, Felix Auger Aliassime won his previous match in straight sets. It was an exceptional serving display by Felix Auger Aliassime as he won 74% of his serving points. Felix Auger Aliassime won 92% of his service games which made him very tough to beat. The match was won by Felix Auger Aliassime due to his handling of pressure as the Canadian won 2 tiebreakers to secure the overall win. Prior to this tournament, Felix Auger Aliassime played the Rio Open where he finished second.
Felix Auger Aliassime and Laslo Dere played each other last week in the final of the 2019 ATP Rio Open. On that occasion, Laslo Dere outclassed Felix Auger Aliassime by winning in straight sets. The final of the Rio Open is the only prior match between Laslo Dere and Felix Auger Aliassime.
As far as this match is concerned, I am going to pick Laslo Dere to win. Dere just beat Felix Auger Aliassime and that result will have an impact on both players. With the confidence from that win, I see Dere getting another win over Felix Auger Aliassime.