Japanese tennis superstar, Kei Nishikori has made it into the third round of the 2019 ATP Australian Open. Nishikori will now take on João Sousa from Portugal.
João Sousa has had a tough road to the third round as both of his matches have lasted 5 sets. In the previous round, João Sousa beat Philip Kohlschreiber. It was a close match where both players served exceptionally well. Sousa was impressive with his serve as he hit 28 aces which allowed him to win 93% of his service games. The concerning statistic for João Sousa was his returning. Sousa only won 2 return games in the entire match which made it very hard for him to gain any advantages over his opponent. João Sousa will need to improve his returning if he wishes to win this match.
Similar to his opponent, both of Kei Nishikori’s matches have also last 5 sets. In the second round, Nishikori beat Ivo Karlovic. It was a close match, but Nishikori won vital points during the final set tiebreaker to get the overall win. Kei Nishikori has been in very good form recently as he won the ATP Brisbane International recently. With the title win recent in his memory, Nishikori looks to be playing with lots of confidence on the court.
Kei Nishikori and João Sousa have played twice in the past with both players winning on 1 occasion. The most recent match between these two players was in 2017 where Kei Nishikori won in straight sets.
Taking everything into consideration, I am going to pick Kei Nishikori to win this match. While both players have played long matches in this tournament, Kei Nishikori has looked much more convincing during his wins. Having recently won an ATP title, Kei Nishikori will be confident heading into this match which is a decisive factor. I see Kei Nishikori winning this match and making.