Canadian tennis superstar, Milos Raonic is set to play against Pierre-Hugues Herbert from France in the third round of the 2019 ATP Australian Open.
Pierre-Hugues Herbert beat the number 24 seed, Hyeon Chung, in the previous round of the tournament. During the win, Herbert returned served exceptionally well as he won 40% of the points played during Chung’s serve. Pierre-Hugues Herbert managed to win 5 return games which gave him a big advantage over his opponent. It is important to note that Pierre-Hugues Herbert struggled with his serve as he had a first serve percentage of only 69% which resulted in him losing 3 service games. Herbert will have to improve his first serve percentage if he wishes to compete in this match.
On the other side of the court, Milos Raonic had a big win the previous round as he eliminated Stan Wawrinka in 4 sets. During the win, Milos Raonic served exceptionally well as he hit 38 aces which allowed him to win 92% of his service games. It was an impressive win for Raonic as the Canadian beat a former Australian Open champion. Milos Raonic has a good record at Melbourne Park as he made the semi-finals of the Australian Open in 2016.
This will be the first time that Pierre-Hugues Herbert and Milos Raonic will be playing each other at an ATP event.
Taking everything into consideration, I see Milos Raonic winning this match. While Pierre-Hugues Herbert has played well, Raonic looks to be back to his best. Milos Raonic will be high on confidence after beating Stan Wawrinka and he is looking to be hitting the ball very cleanly. With a strong record at Melbourne Park, I see Milos Raonic winning this match and making it into the fourth round of the Australian Open.